3w^2+2w-56=0

Solution for 3w^2+2w-56=0 equation:

3w^2+2w-56=0

a = 3; b = 2; c = -56;
Δ = b2-4ac
Δ = 22-4·3·(-56)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*3}=\frac{-28}{6}
=-4+2/3
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*3}=\frac{24}{6}
=4
$